Hello again,
I have got to Cube (Cube A, Cube B)
The first Cube, Cube A is the same a Cube B minus a dimension.
So Cube A is (Dimension 1, Dimension 2, Dimension 3) and Cube B is (Dimension 1, Dimension 2, Dimension 3, Dimension 4)
I would like just to feed Cube B with Cube A and treat Dimension 4 equal to Dimension 3.
So I would like to have a B rule that does this: CubeB [Dimension 1, Dimension 2, Dimension 3, Dimension 4] = Cube A [Dimension 1, Dimension 2, Dimension 3]
where Cube B. Dimension3 is the same a CubeB dimension4 and equal to CubeA. Dimenson 3.
And CubeA dimension 1 = Cube B dimension 1
And CubeA dimension 2 = Cube B dimension 2
What I tried to do is to put this in the Cube A Rules Editor
FEEDERS;
[] => DB (Cube B, !Dimension 1, !Dimension 2, !Dimension 3, !Dimension 3)
But I dont know what to put as SKIPCHECK for the Cube B rules editor in order to activate this feeder (if I have understood properly the inter cube feeder process)
Any idea?
Thankx in advance for your time.
Bye
Nicola
inter cube feeders with one more dimensione
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Re: inter cube feeders with one more dimensione
Hi
Consider:
Consider:
Code: Select all
[]=N:IF(!Dimension 3@=!Dimension 4,DB(Cube A, !Dimension 1, !Dimension 2, !Dimension 3),0);
Best regards,
Wim Gielis
IBM Champion 2024-2025
Excel Most Valuable Professional, 2011-2014
https://www.wimgielis.com ==> 121 TM1 articles and a lot of custom code
Newest blog article: Deleting elements quickly
Wim Gielis
IBM Champion 2024-2025
Excel Most Valuable Professional, 2011-2014
https://www.wimgielis.com ==> 121 TM1 articles and a lot of custom code
Newest blog article: Deleting elements quickly
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- Posts: 43
- Joined: Thu Oct 22, 2009 7:58 am
- OLAP Product: TM1
- Version: 9.5.1
- Excel Version: 2007
Re: inter cube feeders with one more dimensione
Thanxs a lot!!!
It was exactly what I was looking for
Bye
Nicola
It was exactly what I was looking for

Bye
Nicola