Hello All
I have a question on the treatment of an element in the Feeders calculations as following:
Suppose, There is a cube called ABC and XYZ
Cube: ABC Cube: XYZ
dim1: ! Regions dim1: ! Regions
dim2: ! Month dim2: ! Years
Dim3: ! Scenario dim3: ! Scenario
The Strucrure of dim2: ! Months
Month (Consolidation)
Week1 (Child)
Week2 (Child)
Week3 (Child)
Week4 (Child)
The Feeders in the XYZ Cube:
['Actual']=>DB('ABC',!Regions,'Month','Actual-Current Year');
Suppose dimension structured changed to: dim2! Months
Month (leaf)
Week1(leaf)
Week2 (leaf)
Week3 (leaf)
Week4 (leaf)
Rule: Month = week1+week2+week3+week4
Does this"['Actual']=>DB('ABC',!Regions,'Month','Actual-Current Year');" Feeder would work in same manner as it was with prior structure of dim2 !Months
Thanks
Dharav
Treatments of an element in Feeders
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Re: Treatments of an element in Feeders
Hi,
Let me get it clear
Cube XYZ dim structure: Regions, Years, Scenario
Cube ABC dim structure: Regions, Month, Scenario
Correct?
Whats is the dim structure of !Years?
In case of the rule change, weeks would feed Month and Cube XYZ would feed weeks.
Let me get it clear
Cube XYZ dim structure: Regions, Years, Scenario
Cube ABC dim structure: Regions, Month, Scenario
Correct?
Whats is the dim structure of !Years?
In case of the rule change, weeks would feed Month and Cube XYZ would feed weeks.
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Re: Treatments of an element in Feeders
hi dharav,
Feeding to a consolidation is the same as feeding to each ultimate n-level leaf underneath the consolidation separately.
So in your first case
['Actual']=>DB('ABC',!Regions,'Month','Actual-Current Year');
equivalent to
['Actual']=>
DB('ABC',!Regions,'Week1','Actual-Current Year'),
DB('ABC',!Regions,'Week2','Actual-Current Year'),
DB('ABC',!Regions,'Week3','Actual-Current Year'),
DB('ABC',!Regions,'Week4','Actual-Current Year');
If you make your 'Month' element a leaf, you will need to write the feeder in longhand as above.
Feeding to a consolidation is the same as feeding to each ultimate n-level leaf underneath the consolidation separately.
So in your first case
['Actual']=>DB('ABC',!Regions,'Month','Actual-Current Year');
equivalent to
['Actual']=>
DB('ABC',!Regions,'Week1','Actual-Current Year'),
DB('ABC',!Regions,'Week2','Actual-Current Year'),
DB('ABC',!Regions,'Week3','Actual-Current Year'),
DB('ABC',!Regions,'Week4','Actual-Current Year');
If you make your 'Month' element a leaf, you will need to write the feeder in longhand as above.
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Re: Treatments of an element in Feeders
Thank you all for prompt response.
I had the same thought dan. In practical scenario i have more than 4200 elements without having any consolidation and i can not use dummy consolidation here to feed due to some strange business requirements. It would be better to transfer the data through TI instead of Rules.
Thanks Again you all
Dharav
I had the same thought dan. In practical scenario i have more than 4200 elements without having any consolidation and i can not use dummy consolidation here to feed due to some strange business requirements. It would be better to transfer the data through TI instead of Rules.
Thanks Again you all
Dharav
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Re: Treatments of an element in Feeders
Why can't you create a consolidation and hide it from the end user using element security?dharav wrote: i can not use dummy consolidation here to feed due to some strange business requirements